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The speed (v) of ripples on the surface ...

The speed `(v)` of ripples on the surface of waterdepends on surface tension `(sigma)`, density `(rho)` and wavelength `(lambda)`. The square of speed `(v)` is proportional to

A

`sigma/(rho lambda)`

B

`rho/(sigma lambda)`

C

`lambda/(sigma rho)`

D

`rho lambda sigma`

Text Solution

Verified by Experts

The correct Answer is:
a

`v prop sigma^(x)rho^(y)lambda^(z)`
`v=ksigma^(x)rho^(y)lambda^(z)`
`[LT^(-1)]=[MT^(-2)]^(x)[ML^(-3)]^(y)[L]^(z)`
`x+y=0" "," "-2x=-1" "," "-3y+z=1`
`x=1/2" "y=-1/2" "z=-1/2`
Hence, `v=(sigma^(1//2))/(rho^(1//2)lambda^(1//2))`
`v^(2) equiv (sigma/(rho lambda))`
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