If momentum (P), area (A) and time (T) are assumed to be formula :

Options

A. `[PTA^(-1//2)]`
B. `[PT^(-1) A^(1//2)]`
C. `[P^(2)T^(-1)A]`
D. `[PTA^(-1)]`

Answer

b

Explanation

`E=[ML^(2)T^(-2)]`
and Energy can be given by `=("Momentum"xx"Time")/("Area")`
Hence `E=[PTA^(-1)]`
OR
`E prop P^(x)A^(y)T^(z)`
`[ML^(2)T^(-2)]=[MLT^(-1)]^(x)[L^(2)]^(y)[T]^(z)`
on comparing `x=1`
`y=-1" "` Hence `E=[PTA^(-1)]`
`z=1`