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A student performs an experiment for det...

A student performs an experiment for determination of ` g [ = ( 4 pi^(2) L)/(T^(2)) ] , L ~~ 1m` , and he commits an error of `Delta L`. For `T` he takes the time of `n` oscillations with the stop watch of least count ` Delta T` . For which of the following data , the measurement of `g` will be most accurate ?

A

`DeltaL=0.5, DeltaT=0.1, n=20`

B

`DeltaL=0.5, DeltaT=0.1, n=50`

C

`DeltaL=0.5, DeltaT=0.01, n=20`

D

`DeltaL=0.5, DeltaT=0.05, n=50`

Text Solution

Verified by Experts

The correct Answer is:
d
`(Deltag)/g=(Deltal)/(l)+2(DeltaT)/(n T)`
(`Deltal` and `DeltaT` are least, and the number of resdings are maximum.)
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