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Student I ,II , and III perform an exper...

Student `I ,II , and III` perform an experiment for measuring the acceleration due to gravity `(g) ` usinf a simple pendulum. They use lengths of the pendulum and // or record time for different number of oscillations . The observations are shown in the following table . Least count for length ` = 0.1 cm`
`{:(underset(III)underset(II)underset(I)underset()underset()("Student"),underset(20.0)underset(64.0)underset(64.0)underset((cm))underset("Pendulam")("Length of "),underset(4)underset(4)underset(8)underset((n))underset("n Oscillation")("Number of"),underset(9.0)underset(16.0)underset(16.0)underset((s))underset("Period")("Time")):}`
Least count for time `= 0.1 s`.
If `E_(I), E_(II)` , and `E_(III)` are the percentage errors in `g` , i.,e., `((Delta g)/( g) xx 100)` for students I,II , and III, respectively , then

A

`E_(I)=0`

B

`E_(I)` is minimum

C

`E_(I)=E_(II)`

D

`E_(II)` is maximum

Text Solution

Verified by Experts

The correct Answer is:
b

`g=4pi^(2)(l/T^(2))rArr (Deltag)/g=(Deltal)/l+2 (Delta T)/T`
`rArr E=((Deltal)/l+2(DeltaT)/T)xx100`
The greater the valu of T, the lesser the error. Hence fractional error in the first observation is minimum.
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