The dimensions of length are expressed as `G^(x)c^(y)h^(z)`, where G, c and h are the universal gravitational constant, speed of light and Planck's constant respectively, then :

Options

A. `x=(1//2), y=(1//2)`
B. `x=(1//2), z=(1//2)`
C. `y=(-3//2), z=(1//2)`
D. `y= (1//2), z=(3//2)`

Answer

b, c

Explanation

`L=sqrt((hG)/c^(3))=[G^(1//2)c^(-3//2)h^(1//2)]`
`:. X=1/2, y=-3/2, z=1/2`