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A student uses a simple pendulum of exac...

A student uses a simple pendulum of exactly `1m` length to determine `g`, the acceleration due ti gravity. He uses a stop watch with the least count of `1sec` for this and record `40 seconds` for `20` oscillations for this observation, which of the following statement `(s) is (are)` true?

A

Error `DeltaT` in measuring T, the time period, is 0.05 s

B

Error `DeltaT` in measuring T, the time period is, 1 s

C

Percentage error in the determination of g is 5%

D

Percentage error in the determination of g is 2.5 %

Text Solution

Verified by Experts

The correct Answer is:
a, c
`T=40/20=2s`
`(DeltaT)/T=(Deltat)/t=1/40`
`rArr DeltaT=T/40=2/40=0.05 s`
`g=(4pi^(2)Ln^(2))/t^(2)" "`where `t=nT`
`(Deltag)/g=(2 Delta t)/t`
`rArr %` error `=(2 Delta t)/txx100=5%`
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