A monobasic acid solution has pH value of `5`. Its molarity is `0.005 M`. The degree of ionisation of the acid is

Options

A. `5 xx 10^(-3)`
B. `2 xx 10^(-3)`
C. `5 xx 10^(-2)`
D. `2 xx 10^(-2)`

Answer

B

Explanation

`alpha = ([H^(+)])/(C) = (10^(-5))/(5 xx 10^(-3))`
`= 2 xx 10^(-3)`