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If the solubility of AgCl in 0.1 M NaCl...

If the solubility of `AgCl` in `0.1 M` NaCl is (`K_(sp)` of `AgCl = 1.2 xx 10^(-10)`)

A

11

B

9

C

13

D

5

Text Solution

Verified by Experts

The correct Answer is:
B
`K_(sp)` of `MOH = 1 xx 10^(-10) M^(2)`
`P^(H) = ?`
`MOH` is `AB` type of salt
`:. K_(SP) = S^(2)`
`[OH^(-)] = S`
`S = sqrt(K_(SP)) = sqrt(1 xx 10^(-18))`
`S = 10^(-5)`
`[OH^(-)] = 10^(-5)`
`P^(OH) = ="log"_(10)[OH^(-)] = - "log"_(10)10^(-5) = 5`
`P^(H) + P^(OH) = 14`
`:. P =14 - 5 = 9`
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