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The height at which the acceleration due...

The height at which the acceleration due to gravity becomes `(g)/(9)` (where g = the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth is

A

2 R

B

`(R )/(sqrt(3))`

C

`(R )/(2)`

D

`sqrt(2) R`

Text Solution

Verified by Experts

The correct Answer is:
A
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