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Suppose the chances of hitting a target ...

Suppose the chances of hitting a target by a person X is 3 times in 4 shots, by Y is 4 times in 5 shots, and by Z is 2 times in 3 shots. They fire simultaneously exactly one time. What is the probability that the target is damaged by exactly 2 hits ?

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The correct Answer is:
`= 12/60 + 6/60 + 8/60 = (12+6+8)/(60) = 26/60 = 13/30`
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