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Give the expression for instantaneous di...

Give the expression for instantaneous displacements of a projectile along 'x' and 'y' direction .

Text Solution

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Along the 'x direction, x=`(v_0costheta_0)t`
and along the 'y' direction, y=x`tantheta_0-(x^2)/(R )tantheta_0`
where R-is the range of the particle
Also `y=xtantheta_0-(gx^2)/(2(v_0costheta_0)^2)`
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