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Give the expression for the time of flig...

Give the expression for the time of flight and the maximum height reached by the projective.

Text Solution

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(a) Time of flight `T=(2v_0sintheta_0)/(g)=(2(v_0)_y)/g`
(b) maximum height H`=((v_0sintheta_0)^2)/(2g)=((v_0)^2)/(2g)`
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