Obtain an expression for Horizontal Range of a projectile.

Explanation

Expression for range of the projectile
We know that `(v_0costheta)` remains constant.
Instantaneous distance along the horizontal is given by
`x(v_0costheta)t`
for x=R (range of the projectile), t=T=time of flight.
Hence `R=(v_0costheta)((2v_0sintheta)/(g))` Note: `R=2/gv_(0x)v_(0y)`
i.e. `R(v_0sin2theta)/(g)` where `sin2theta=2sinthetacostheta`
Hence `Rpropv_0^2` for the given angle of projection