If a vector`vecA` makes an angle of `60^(@)` with respect to the X-axis, then write the two rectangular components of the vector.

Explanation

From the figure,
`sintheta=(AB)/(OA)`
i.e., `A_y=vec(OA)sintheta`
or `A_y=Asintheta`
Similarly `costheta=(OB)/(OA)`
and `A_X=vec(OA)costheta`
i.e, `A_Xcostheta`
`vecA_x=Acosthetahati" and "vecA_y=Asinthetahatj` hus`A_X=Acos60^(@)=A/2`
and `A_Y=Asin60^(@)=(sqrt3)/(2)A`