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The angle between the vectors barA and b...

The angle between the vectors `barA` and `barB` is `60^(@)`. What is the ratio of `barA.barB` and `|barAxxbarB|` ?

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Verified by Experts

`vecAvecB=AB costheta" and " |vecAxxvecB|=Absintheta`
Hence `(vecAvecB)/(|vecAxxvecB|)=cottheta=cot60^(@)=0.577`
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