Calculate the angular acceleration of a particle executing uniform circular motion of radius 0.60m and speed `5ms^(-1)`.

Explanation

Given, r=0.60m,`v=5ms^(-1)`
We know that `a=(v^2)/r=((5)^2)/(0.6)=41.7ms^(-1)`
but `a=rprop`
Hence angular acceleration`prop=a/r=(41.7)/(0.6)`
i.e, `prop=69.5 rad s^(-2)`