A stone tied to one end of a string of radius 0.6m is whirled in a horizontal circle with an angular speed of 120rpm. Calculate the radial acceleration and force exerted by the stone of mass 0.010 kg on the agent.

Explanation

Given `r=0.6m,omega=(120xx2pi)/(60)rad s^(-1)`
i.e `omega=12.568 rad s^(-1)`
Radial acceleration `a=omega2r=(12568)^2xx(0.6)=94.8ms^(-2)`
Force on the agent`=ma=0.01xx94.8=0.948N`