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Obtain the value of specific heat of wat...

Obtain the value of specific heat of water in terms of `Jkg^(-1)K^(-1)`.

Text Solution

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Specific heat capability of water is approximately = 9R
i.e. C = (9R) `mole^(-1) K^(-1)`.
But 1 mole of water = 0.018kg
Hence specific heat `S = (9xx8.314)/(0.018)Jkg^(-1)K^(-1)`
`Sapprox4157kg^(-1)K^(-1)` `("Specific heat of water is" 4190 Jkg^(-1)K^(-1))`
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