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Write the molecular orbital electronic c...

Write the molecular orbital electronic configuration for carbon monoxide molecule. Calculate its bond order and comment on its magnetic property.

Text Solution

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`sigma1s^(2) sigma^(**) 1s^(2) sigma 2s^(2) sigma^(**) 2 s^(2) pi 2 px^(2)=pi 2 py^(2)`
bond order `=(N_(B)-N_(A))/2=1/2(8-4)=2`
Since there are no unpaired electron it is diamagnetic in nature.
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