Home
Class 11
PHYSICS
A body slows down such that v^(2) is var...

A body slows down such that `v^(2)` is varying linearly with displacement 's' as shown in the Fig.4.5. Assuming rectiliear motion, find the :
(a) acceleration of the body
(b) speed of the body when it just cross `100 m`
(c) `v - s` group

Text Solution

Verified by Experts

(a) The slope of `v^(2) - s` graph, that is `(d(v^(2)))/(ds)` is equal to `(800 - 2400)/(200 - 80) = - (40)/(3) m//s^(2)`, obtained from the given
Since, `(d(v^(2)))/(ds) = 2a`
and `(d(v^(2)))/(ds) = - (40)/(3)`,
we have `a = (-20)/(3) m//s^(2)`
(b) From the graph, `(v^(2) - 2400)/(200 - 80) = (-40)/(3)`
This yields `v = 20 sqrt2 m//s`
(c) Considering a point `P (s, v^(2))` on the `v^(2) -s` graph, equation of AB is given by `(v^(2) - 2400)/(s - 80) = - (40)/(3)`. It yield `v = sqrt((40)/(3) (260 - s))` as plotted in Fig.4.58
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A STRAIGHT LINE

    GRB PUBLICATION|Exercise Problems and Practice|16 Videos
  • MOTION IN A STRAIGHT LINE

    GRB PUBLICATION|Exercise Objective question|168 Videos
  • MOTION IN A STRAIGHT LINE

    GRB PUBLICATION|Exercise Comprehension type Queston|14 Videos
  • FRICTION AND CIRCULAR MOTION

    GRB PUBLICATION|Exercise Comprehension type|11 Videos
  • MOTION IN TWO AND THREE DIMENSIONS

    GRB PUBLICATION|Exercise All Questions|210 Videos

Similar Questions

Explore conceptually related problems

The velocity of a body in rectilinear motion is determined by the formula v = 3t + t^(2) . What acceleration will the body have 4s after the start ?

The displacement of body is given by s = 4 + 2t^4 . The acceleration of the body at the end of 1 s from the start is :

A body of 4 kg mass placed on a smooth horizontal surface experiences a force varying with displacement of block as shown in figure-3.7. Find the speed of the body when force ceases to act on it.

If the velocity of a body related to displacement x is given by v=sqrt(5000+24x) m/s, then the acceleration of the body is _______ m//s^(2) .

The change in the velocity of a body is (12.5pm 0.2)m//s in a time (5.0pm0.3)s. Find the average acceleration of the body within error limits.

A body cover 20 m in 2 s and another 20 m in next 4s. Arrange the following steps in sequential order to find th average velocity of the body . (A) Find the displacements of the body in first 2s and next 4 s from the given data. (B) find the displacements of the body . (C) find the total time taken by the body to complete the total displacement . (D) Use the formula, average velocity = ("total displacement")/(" Total time taken")