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For the one dimensional motion, describe...

For the one dimensional motion, described by `x=t-sint`

A

`x (t) gt 0 " for all " t gt 0`

B

`v (t0 gt 0 " for all " t gt 0`

C

`a (t) gt 0 " for all " t gt 0`

D

`v(t)` lies between 0 and 2

Text Solution

Verified by Experts

The correct Answer is:
A, D
`x = t - sin t`
for `t gt 0`
`sin t lt t`
`v = (1 - cos t)`
Since, `-1 le cos t le 1`
Hence, `0 le v le 2`
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