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A ball is allowed free to fall from heig...

A ball is allowed free to fall from height 'H' which rebounds back to maximum height 'h' (H). Take upward as the direction and initial position on origin

Text Solution

Verified by Experts

The correct Answer is:
`a rarr q; b rarr s; c rarr r; d rarr t`
`v^(2) = 2gh`
It means velocity vs displacement graph is parabolic. Distance always increases hence distance vs time graph is
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Knowledge Check

  • A body is allowed to fall on the ground from a height h_(1) . If it is rebound to a height h_(2) then the coefficient of restitution is:

    A
    `(h_(2))/(h_(1))`
    B
    `sqrt((h_(2))/(h_(1)))`
    C
    `(h_(1))/(h_(2))`
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  • A ball takes t seconds to fall from a height h_(1) and 2_(t) seconds to fall from height h_(2) then find the ratio of h_(1 ) and h_(2 )

    A
    `4:1`
    B
    `3:1`
    C
    `1:4`
    D
    `1:3`

  • A ball is dropped on a horizontal surface from height h. If it rebounds upto height (h)/(2) after first collision then coefficient of restitution between ball and surface is

    A
    `(1)/(sqrt2)`
    B
    `(1)/(2)`
    C
    `(1)/(4)`
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