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A lift is moving up with a constant reta...

A lift is moving up with a constant retardation of `2 m//s^(2)`. When its upward velocity is 5 m/s, a boy in the lift tosses a coin, imparting it an upward velocity of 3 m/s, w.r.t. himself. His fingers at the moment of toss are midway between the floor and cciling, whose total height is 2 m. Displacement of coin when it hits the ground is x metre (in earth frame). Value of x is : `(g = 10 m//s^(2))`

Text Solution

Verified by Experts

The correct Answer is:
3
Initial velocity of coin `= 2 m//s`
Acceleration `= - 10 m//s^(2)`
Now, `h = ut + (1)/(2) a t^(2)`
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