2 kg box rests on a frictionless of angle `30^(@)` supported by a spring. The spring stretches by 3cm
(a) Find the force constant of the spring
(b) if the box is pulled down the incline 5 cm from its equilibrium position and released what will be its initial acceleration? `(g=10m//s^(2))`

Answer

`(a) 333.33 N//m`
(b) `8.33 m//s^(2)`

Explanation

(a) `Mg sin theta =Kx`
`2xx10xx1/2=Kxx3/100`
`K=1000/3 N//m`
(b) `kx-Mg sin theta =Ma`
`1000/3xx8/100-2xx10xx1/2=2xxa`
`a=50/6m//sec^(2)`