Two masses `m_(1)` and `m_(2)` are connected to the ends of a massless string that passes over a pulley fixed at the top of a double incline as shown. Assuming `m_(1) gtm_(2)` acceleration of the system is:

Options

A. `(m_(1)g sin theta_(1)+m_(2)g sin theta_(2))/(m_(1)+m_(2))`
B. `(m_(1)g sin theta_(1)-m_(2) g sin theta_(2))/(m_(1)-m_(2))`
C. `(m_(1)g sin theta_(1)-m_(2) g sin theta_(2))/(m_(1)+m_(2))`
D. `((m_(1)+m_(2))(sin theta_(1)+sin theta_(2))g)/(m_(1)-m_(2))`

Answer

C

Explanation

`m_(1)g sin theta_(1)-T=m_(1)a`
`T-m_(2)g sin theta_(2)=m_(2)a`
By solving this, we get acceleration.