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Answer the following : (a) You are giv...

Answer the following :
(a) You are given a tread and a metre scale. How will you estimate the diameter of the thread ?
(b) A screw gauge has a pitch of `1.0` mm and 200 divisions on the circular scale. Do you think it is possible to increase the accuracy of the screw gauge arbitratily by increasing the number of divisions on the circular scale ?
(c) The mean diameter of a thin brass rod is to be measured by vernier callipers. Why is a set of 100 measurements of the diameter expected to yield a more reliable estimate than a set of 5 measurement only ?

Text Solution

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(a) Wrap the thread on a uniform smooth rod in such a way that the coils thus formed are very close to each other. Measure the length of the thread using a metre scale. The diameter of the thread is given by the relation,
Diameter=`("Length of thread")/("Number of turns")`
(b) It is not possible to increase the accuracy of a screw gauge by increasing the number of divisions of the circular scale. Increasing the number divisions of the circular scale will increase its accuracy to a certain extent only.
(c) A set of 100 measurements is more reliable than a set of 5 measurements because random errors involved in the former are very less as compared to the latter.
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(a) You are given a thread and a metre scale. How will you estiate the diameter of the thread ?(b) A screw gauge has pitch of 1.0 mm and 200 division on the circular scale. Do you think it is possiblel to increase the accuracy of the gauge arbitrarily by increasing the number of division on the circular scale ? (c ) The mean diameter of a thin brass rod is to be measured by vernier callipers. Why is a set of 100 measurements of the diameter expected to yield a more reliable estimate then a set 5 measurements only?

Accuracy of screw gauge can be increased by …………. The number of divisions on circular scale.

Knowledge Check

  • A screw gauge has 1.0mm pitch and 200 divisions on the ciruclar scale. The least count of the instrument is

    A
    `5xx10^(-3)mm`
    B
    `5xx10^(-4)mm`
    C
    `5xx10^(-2)mm`
    D
    `5xx10^(-5)mm`
  • A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale : The pitch of the screw gauge is:

    A
    `0.25 mm`
    B
    `0.5 mm`
    C
    `1.0 mm`
    D
    `0.01 mm`
  • Without changing the number of divisions on the circular scale, if the pitch of the screw gauge is halved, then its accuracy of measurement

    A
    decreases
    B
    increases
    C
    remains unaffected
    D
    increases or decreases depending on the weight.
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