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A parallel coherent beam of light falls ...

A parallel coherent beam of light falls on fresnel biprism of biprism of refractive index `mu` and angle `alpha` .The fringe width on a screen at a distance `D` from biprism will be (wavelength =`lambda`)

Text Solution

Verified by Experts

The correct Answer is:
`(lambda)/(2(mu - 1)alpha)`
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