The motion of a particle of mass m is described by `y =ut + (1)/(2) g t^(2)` . Find the force acting on the particale .

Explanation

We know
y = ut + `1/2 yt^(2)`
Now,
`nu` = dy/dt = u + gt
acceleration , a = d`nu`/dt = g
Then the force is given by Eq.(5.5)
F = ma = mg
Thus the given equation describes the motion of a particle under acceleration due to gravity and y is the position coordinate in the direction of g.