Detrmine the maximum acceleration of the train in which a box lying on the floor will remain stationary given that the coefficient of static friction between the box and the train s floor is 0.15 given `g = 10 m//s^(2)` .

Explanation

Since the acceleration of the box is due to the static friction.
ma = `f_s` `le` `mu_s`N = `mu_s`mg
i.e. a `le` `mu_s`g
`therefore` `a_max` = `mu_s`g = 0.15 `xx` 10 m `s^(-2)`
= `1.5 m s^(-2)`