Home
Class 11
PHYSICS
A body of mass 5 kg is acted upon by two...

A body of mass 5 kg is acted upon by two perpendicular forces 8 N and 6 N Give the magnitude and direction of the acceleration of the body.

Text Solution

Verified by Experts

Here m = 5 kg
`F_1` = 8N and `F_2` = 6 N
The resultant force on the body
F = `sqrt (F_1^(2) + F_2^(2))` = `sqrt (8^(2) + 6^(2))` N
`implies` F = `sqrt ( 64 + 36 ) ` N = 10 N
The acceleration , a = F / m
`implies` a = 10 / 5 = 2 `ms^(-2)` in the same direction as the resultant force.
The direction of acceleration ,
tan`beta` = 6/8 = 3/4 = 0.75
or, `beta` = `tan^(-1)`(0.75)
= `37^(@)` with 8 N force.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • LAWS OF MOTION

    NCERT|Exercise EXERCISE|40 Videos
  • KINETIC THEORY

    NCERT|Exercise EXERCISE|14 Videos
  • MECHANICAL PROPERTIES OF FLUIDS

    NCERT|Exercise EXERCISE|31 Videos

Similar Questions

Explore conceptually related problems

A body of mass 5 kg is acted upon by two perpendicular forces of 4 N and 3 N. What is the magnitude and direction of acceleration ?

A block of mass 5 kg is acted upon two perpendicular force 7 N and 24N . Find the magnitude and the direction of acceleration of the block.

Knowledge Check

  • A body of mass 5kg is acted upon by two perpendicular force 8N and 6N, find the magnitude and direction the acceleration

    A
    `3 ms^(-2), theta=cos^(-1)(0.8) " from "8 m`
    B
    `2 ms^(-2), theta=cos^(-1)(0.6) " from "6 m`
    C
    `3 ms^(-2), theta=cos^(-1)(0.9) " from "6 m`
    D
    `5 ms^(-2), theta=cos^(-1)(0.81) " from "8 m`
  • A body of mass 10 kg is acted upon by two perpendicular forces , 6 N and 8 N . The resultant acceleration of the body is

    A
    `1 m s^(-2)` at an angle of `tan^(-1) ((3)/(4))` w.r.t. 6 N force
    B
    `0.2 m s^(-2) ` at an angle of `tan^(-1)((4)/(3))` w.r.t. 6 N force
    C
    `1 m s^(-2)` at an angle of `tan^(-1) ((3)/(4))` w.r.t. 8 N force
    D
    0.2 `ms^(-2)` at an angle of `tan^(-1)((3)/(4))` w.r.t. 8 N force
  • A body of mass 10kg is acted upon by two per pendicular forces 6N and 8N . The resultant ac-celeration of the body is .

    A
    `1 ms^(-2)` at angle of `tan^(-1)((4)/(3)) 6N` force .
    B
    `0.2 ms^(-2)` at an angle of `tan^(-1)((4)/(3))` w.r.t `6N` force .
    C
    `1 ms^(-2)` at an angle of `tan^(-1)((4)/(3))` w.r.t `8N` force .
    D
    `0.2 ms^(-2)` at an angle of `tan^(-1)((4)/(3))` w.r.t `8N` force .
  • Similar Questions

    Explore conceptually related problems

    A body of mass 2kg is acted upon by two forces,each of magnitude 1N,making an angle of 60^(@) with each other.The acceleration of the body in ms^(-2) is ?

    A body of mass 2 kg is acted upon by two forces 2N and 5N in the direction of hati + hatj and hatj-hatk respectively. If the body is displaced from (3,-2, 1) to (-1, 2, 3) (Positions are in m), then work done is

    When two perpendicular forces 9.0 N (toward positive x) and 7.0 N (toward positive y) act on a body of mass 6.0 kg, what are the (a) magnitude and (b) direction of the acceleration of the body ?

    A body of mass 10kg is acted upon by two perpendicular force, 6N . The resultant acceleration of the body is.

    A force of a given magnitude acts on a body . The acceleration of the body depends on the