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Let f (x) = 10 - |x-5| , x in R, then th...

Let f (x) = 10 - |x-5| , `x in R,` then the set of all values of x at which f (f(x)) is not differentiable is

A

{0,5,10}

B

{5,10}

C

{0,5,10,15}

D

{5,10,15}

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The correct Answer is:
To find the set of all values of \( x \) at which \( f(f(x)) \) is not differentiable, we will follow these steps: ### Step 1: Define the function \( f(x) \) The function is given as: \[ f(x) = 10 - |x - 5| \] ### Step 2: Find \( f(f(x)) \) To find \( f(f(x)) \), we first substitute \( f(x) \) into itself: \[ f(f(x)) = f(10 - |x - 5|) \] ### Step 3: Substitute \( f(x) \) into the function Now, we need to evaluate \( f(10 - |x - 5|) \): \[ f(10 - |x - 5|) = 10 - |(10 - |x - 5|) - 5| \] This simplifies to: \[ = 10 - |5 - |x - 5|| \] ### Step 4: Analyze the expression \( |5 - |x - 5|| \) The expression \( |5 - |x - 5| \) can change based on the value of \( x \). We need to find the critical points where this expression is not differentiable. ### Step 5: Identify points where \( |x - 5| \) changes The expression \( |x - 5| \) changes at \( x = 5 \). Therefore, we need to consider the cases for \( x \): 1. **Case 1:** \( x < 5 \) - Here, \( |x - 5| = 5 - x \) - Thus, \( |5 - |x - 5|| = |5 - (5 - x)| = |x| \) 2. **Case 2:** \( x = 5 \) - Here, \( |x - 5| = 0 \) - Thus, \( |5 - |x - 5|| = |5 - 0| = 5 \) 3. **Case 3:** \( x > 5 \) - Here, \( |x - 5| = x - 5 \) - Thus, \( |5 - |x - 5|| = |5 - (x - 5)| = |10 - x| \) ### Step 6: Find points of non-differentiability The function \( f(f(x)) \) will not be differentiable at the points where \( |5 - |x - 5|| \) changes, which are: - At \( x = 5 \) (where \( |x - 5| \) changes) - At \( x = 10 \) (where \( |10 - x| \) changes) ### Conclusion The set of all values of \( x \) at which \( f(f(x)) \) is not differentiable is: \[ \{ 5, 10 \} \]
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