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Calculate 7^(log g(3)5) + 3 ^(log(5)7 ) ...

Calculate `7^(log g_(3)5) + 3 ^(log_(5)7 ) - 5 ^(log_(3)7) - 7 ^(log_(5)3)`

A

1

B

0

C

`7^(log_(3)5`

D

None

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \( 7^{\log_3 5} + 3^{\log_5 7} - 5^{\log_3 7} - 7^{\log_5 3} \), we will use the logarithmic identity: \[ a^{\log_b c} = c^{\log_b a} \] ### Step 1: Rewrite the terms using the logarithmic identity 1. **First Term**: \[ 7^{\log_3 5} = 5^{\log_3 7} \] (Using the identity with \( a = 7, b = 3, c = 5 \)) 2. **Second Term**: \[ 3^{\log_5 7} = 7^{\log_5 3} \] (Using the identity with \( a = 3, b = 5, c = 7 \)) ### Step 2: Substitute back into the expression Now substituting these back into the original expression: \[ 5^{\log_3 7} + 7^{\log_5 3} - 5^{\log_3 7} - 7^{\log_5 3} \] ### Step 3: Simplify the expression Notice that \( 5^{\log_3 7} \) and \( -5^{\log_3 7} \) cancel each other out, and similarly \( 7^{\log_5 3} \) and \( -7^{\log_5 3} \) also cancel each other out: \[ 0 \] ### Final Result Thus, the final result is: \[ \boxed{0} \] ---
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