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int[1+tanx.tan(x+alpha)]dx is equal to...

`int[1+tanx.tan(x+alpha)]dx` is equal to

A

`cosalpha.l n|sinx/sin(x+alpha)|+C`

B

`tanalpha.l n|sinx/sin(x+alpha)|+C`

C

`cotalpha.l n|sec(x+alpha)/secx|+C`

D

`cotalpha.l n|cos(x+alpha)/cosx|+C`

Text Solution

Verified by Experts

The correct Answer is:
C
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