Which of the following reactions will give result as alkane as major product ?

Options

A.
B.
C.
D.

Explanation

To determine which reactions will yield alkanes as the major product, we need to analyze the given options based on the type of reagents and the nature of the alkyl halides involved.

### Step-by-Step Solution:

1. **Identify the Reagents**: The question provides four options involving different reagents. The key reagents mentioned are lithium aluminum hydride (LiAlH4) and sodium borohydride (NaBH4), both of which are known to be strong reducing agents.

2. **Understand the Reaction Mechanism**:
- **Reducing Agents**: Lithium aluminum hydride and sodium borohydride can reduce alkyl halides (1° and 2°) to alkanes.
- **Elimination vs. Reduction**: For tertiary alkyl halides, the reaction tends to favor elimination, producing alkenes instead of alkanes.

3. **Analyze Each Option**:
- **Option A**: If it involves a 1° or 2° alkyl halide with LiAlH4 or NaBH4, it will yield an alkane.
- **Option B**: Similar to option A, if it involves 1° or 2° alkyl halides, it will also yield an alkane.
- **Option C**: If this option involves a 3° alkyl halide, it is likely to undergo elimination rather than reduction, leading to the formation of an alkene instead of an alkane.
- **Option D**: If it involves a 1° or 2° alkyl halide, it will yield an alkane.

4. **Conclusion**: Based on the analysis:
- Options A, B, and D will produce alkanes as the major product.
- Option C will not produce an alkane due to the elimination reaction occurring with the 3° alkyl halide.

### Final Answer:
The reactions that will give alkanes as the major product are **Option A, B, and D**.