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DIPTI PUBLICATION ( AP EAMET)-INDEFINITE INTEGRATION -EXERCISE 1A
- int sec^(2)"cosec"^(2) x dx=
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- int 1/(1+cos2x)dx=
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- int (1+sin^(2)x)/(1+cos 2x)dx=
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- int (a+b sinx)/(cos^(2)x)dx=
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- int (2-3cosx)/(sin^(2)x)dx=
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- int sqrt(1-sin2x)dx=
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- If x in (-pi//2, pi//2) then int sqrt(1+cos 2x)dx=
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- int (sinx+cosx)/(sqrt(1+sin 2x))dx=
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- int ( sin^(3)x+cos^(3)x)/(sin^(2)x cos^(2)x)dx=
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- int (3 cos^(2)x+4 sin^(2)x)/(cos^(2)xsin^(2)x)dx=
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- int (a cos^(3)x+b sin^(3)x)/(cos^(2)x sin^(2)x)dx=
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- If int (sin^(8)x-cos^(8)x)/(1-2sin^(2)cos^(2)x)dx=A sin 2x+B, then A=
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- int (e^(x)dx)/(cosh x + sin hx)=
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- int (sin hx)/(1+sin h^(2)x)dx
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- int sqrt(1 + 2 cot x ( cot x + cosecx ) ) dx =
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- int (1-cosx)"cosec"^(2)x dx=f(x)+c rArr f(x)=
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- int (1-cosx)"cosec"^(2)x dx=f(x)+c rArr f(x)=
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- int (x^(2)-1)/(x^(2)+1)dx=
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- int (x^(4))/(x^(2)+1)dx
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- int (x^(5))/(x^(2) + 1) dx =
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