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int sec x log (sec x+ tan x)dx=...

`int sec x log (sec x+ tan x)dx=`

A

`[log (sec x +tan x)]^(2)+c`

B

`(1)/(2) [log (sec x-tanx)]^(2)+c`

C

`(1)/(2)[log (sec x+ tan x)]^(2)+c`

D

`(1)/(3)[log (sec x+ tan x)]^(2)+c`

Text Solution

Verified by Experts

The correct Answer is:
C
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