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It int (3x-2)/((x-1)(x+2)(x-2))dx=A log ...

It `int (3x-2)/((x-1)(x+2)(x-2))dx=A log |x-1|B log |x+2|+C log |x-3|+C` `then the ascending order of A,B,C is

A

A,B,C

B

B,A,C

C

C,A,B

D

C,B,A

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