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The limit underset( x rarr a ) ("Lim") (...

The limit `underset( x rarr a ) ("Lim") (2 -( a)/(x))^(tan ((pix)/( 2a)))` is equal to

A

`e^(-a //pi)`

B

` e^(-2a //pi)`

C

` e^(-2 //pi )`

D

1

Text Solution

Verified by Experts

The correct Answer is:
C
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MOTION-LIMIT-EXERCISE -1
  1. underset( x rarr pi //2) ("Lim") ( 2 ^(cos x) - 1)/( x ( x-pi //2))= ...

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  2. lim(x->0)((4^x-1)^3)/(sin(x/p)ln(1+(x^2)/3) is equal to

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  3. The limit underset( x rarr a ) ("Lim") (2 -( a)/(x))^(tan ((pix)/( 2a)...

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  4. underset( x rarr oo) ( "Lim") ((x+ 2)/( x-2))^(x+1)=

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  5. The value of underset( x rarr pi //4) ("Lim") ( 1+[x])^(1//ln( tan x)...

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  6. lim(x->oo) ((x^2-2x+1)/(x^2-4x+2))^x is equal to

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  7. underset( x rarr 0 ) ("lim") ( cos mx )^(n//x^(2))

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  8. If lim(x -> oo) (1 + a/x + b/x^2)^(2x)= e^2 then the values of a and ...

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  9. underset( x rarr0 ) ( "lim" )( cot ((pi)/( 4) + x ))^("cosecx")=

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  10. lim(x->oo)(sin(1/x)+cos(1/x))^x

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  11. lim(x->oo) (root(3)(1+x)-root(3)(1-x))/x

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  12. underset( x rarr 1 )("lim")( root ( 3)(7+x^(3))- sqrt( 3 +x^(2)))/( x-...

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  13. ABC is an isosceles triangle described in a circle of radius r.If AB=...

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  14. The figure shows a right triangle with its hypotenuse OB along the y-a...

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  15. lim(n->oo){(n/(n+1))^alpha+sin(1/n)}^n where alpha epsilon Q is equal ...

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  16. underset( x rarr 0 ) ( "lim")( x tan 2x - 2x ta n x )/(( 1- cos 2x)^(...

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  17. If underset( x rarr0 )("lim")((sin nx) [ ( a-n ) nx - 2 tan x])/( x^(2...

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  18. lim[n->oo][5^[n+1]+3^n-2^[2n]]/[5^n+2^n+3^[2n+3]]

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  19. the value of lim(x->0)(cos(sinx)-cosx)/x^4 is equal to:

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  20. lim[x->0][e^[-x^2/2]-cosx]/[x^3sinx]

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