Given `B=45^(@), c= sqrt(12), b= sqrt(8)`, solve the triangle.

If, in DeltaABC, a = sqrt(2), b = sqrt(3), c = sqrt(5) , then the area of Delta ABC is

In a DeltaABC , if a = 40, c=40sqrt(3) and B=30^(@) , then the triangle is

In Delta ABC, if sin A+sin B+sin B+sin C=1+sqrt(2) and cos A+cos B+cos C=sqrt(2) then the triangle is

If in any Delta ABC,B=60^(@) and b:c=sqrt(3):sqrt(2), then find A.

In a DeltaABC , if A=45^(@) , b=sqrt(6) , a=2, then B=

The sides a,b and c of a triangle satisfy sqrt(a)+sqrt(b)=sqrt(c) the triangle is

In Delta ABC if sin B cos C=(sqrt(3)-1)/(sqrt(3)) and sin C cos B=(1)/(sqrt(3)), then the triangle is

In Delta ABC if sin B cos C=(sqrt(3)-1)/(sqrt(3)) and sin C cos B=(1)/(sqrt(3)), then the triangle is

Prove that the area of an equilateral triangle is equal to (sqrt(3))/4a^2, where a is the side of the triangle. GIVEN : An equilateral triangle A B C such that A B=B C=C A=adot TO PROVE : a r( A B C)=(sqrt(3))/4a^2 CONSTRUCTION : Draw A D_|_B Cdot