Home
Class 12
PHYSICS
A taut string for which mu = 5.00 xx 10^...

A taut string for which `mu = 5.00 xx 10^(-2) kg//m` under a tension of `80.0N`. How much power must be supplied to the string to generate sinusoidal waves at a frequency of `60.0 Hz` and an amplitude of `6.00 cm`?

Text Solution

Verified by Experts

The wave speed on the string is
`v = sqrt((T)/(mu)) =((80.0N)/(5.00xx10^(-2)kg//m))^(1//2) = 40.0 m//s`
Because ` f = 60Hz`, the angular frequency `omega` of the sinusoidal wave on the string has the value
`omega = 2pif =2pi (60.0Hz) = 377 s^(-1)`
Using these values in following equation for the power, with A = ` 6.00 xx 10^(-2)`m, gives
` p = (1)/(2) muomega^(2)A^(2)v`
` = (1)/(2) (5.00 xx 10^(-2) kg//m) (377s^(-1))^(2) xx (6.00 xx 10^(-2) m)^(2) (40.0 m//s)`
` = 512 W`.
Promotional Banner

Topper's Solved these Questions

  • WAVE MOTION

    MOTION|Exercise Questions For Practice|6 Videos
  • WAVE MOTION

    MOTION|Exercise EXERCISE -1|13 Videos
  • VECTOR & CALCULUS

    MOTION|Exercise EXERCISE -4 (LEVEL - II) PREVIOUS YEAR|15 Videos
  • WAVE OPTICS

    MOTION|Exercise EXERCISE - 4 (Level - II) Previous Year | JEE Main|16 Videos

Similar Questions

Explore conceptually related problems

Power supplied to a vibrating string: A string with linear mass density mu=5.00xx10^(-2) kg//m is under a tension of 80.0 N. how much power must be supplied to the string to generate sinusoidal waves at a frequancy of 60.0 HZ and an amplitude of 6.00 cm?

A stretched rope having linear mass density 5xx10^(-2)kg//m is under a tension of 80 N . the power that has to be supoplied to the rope to generate harmonic waves at a frequency of 60 Hz and an amplitude of (2sqrt2)/(15pi)m is

A taut string for which mass per unit length mu=5.0xx10^(-2)kg//m is under tension of 80N. How much power in watt upto one decimal points mus be supplied to the string to generate siusodial be supplied to the string to generate sinusoidal wave at a frequency of 6.0Hz and amplitude of 6.00cm

A string 1 m long with mass 0.1 g cm^(-1) is under a tension of 400 N.Find is fundamental frequency of vibration.

The mass of a string is 5.0 xx 10^(-3) kg, and it is stretched so that the tension in it is 180 N. A transverse wave traveling on this string has a frequency of 260 Hz and a wavelength: of 0.60 m. What is the length of the string?

A piano string having a mass per unit length equal to 5.00 xx 10^(3)kg//m is under a tension of 1350 N , Find the speed with which a wave travels on this string.

A string of linear mass density 5.0 xx 10^-3 kg//m is stretched under a tension of 65 N between two rigid supports 60 cm apart. (a) If the string is vibrating in its second overtone so that the amplitude at one of its antinodes is 0.25 cm, what are the maximum transverse speed and acceleration of the string at antinodes? (b) What are these quantities at a distance 5.0 cm from an node?

In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2xx10^(10)Hz and amplitude 48V//m . The wavelength of the wave will be-