Home
Class 12
PHYSICS
Each of the two strings of length 51.6 c...

Each of the two strings of length `51.6 cm` and `49.1 cm` are tensioned separately by `20 N` force. Mass per unit length of both the strings is same and equal to `1 g//m`. When both the strings vibrate simultaneously, the number of beats is

A

3

B

5

C

7

D

8

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • WAVE MOTION

    MOTION|Exercise Exercise - 3 Section - B (Previous Years Problems)|7 Videos

  • WAVE MOTION

    MOTION|Exercise Exercis -2 (Objective Problems |NEET| )|14 Videos

  • VECTOR & CALCULUS

    MOTION|Exercise EXERCISE -4 (LEVEL - II) PREVIOUS YEAR|15 Videos

  • WAVE OPTICS

    MOTION|Exercise EXERCISE - 4 (Level - II) Previous Year | JEE Main|16 Videos

Similar Questions

Explore conceptually related problems

Each of the strings of length 51.6 cm and 49.1 cm are tensioned separately by 20 N force. Mass per unit length of both the strings is the same and equal to 1gm^(-1) . When both the strings vibrate simultaneoulsy the number of beats is

A string 50 cm long is under a tension of 20N force. Caculate the frequency of fundamental mode given that mass of the string is 1 g.

A string of 7 m length has a mass of 0.035 kg. If tension in the string is 60.5 N, then speed of a wave on the string is :

A vibrating string of certain length l under a tension T resonates with a maode corresponding to the first overtone (third harmonic) of an air column of length 75cm inside a tube closed at one end. The string also gereates 4 beats per second when excited along with a tuning fork of frequency n . now when the tension of the string is slightly increased the number of beats reduces 2 per second. assuming the velocity of sound in air ti be 340 m//s , the frequency n of the tuning fork in Hz is

A mass of 5 kg is tied to a string of length 1.0 m and is rotated in vertical circle with a uniform speed of 4m//s . The tension in the string will be 130 N when the mass is at (g= 10 m//s^2 )

Two light strings of length 4cm and 3 cm are tied to a bob of weight 500 gm .The free ends of the strings are tied to pegs in the same horizontal line and separated by 5 cm .The ratio of tension in the longer string to that in the shortest string is

A string of 7 m length has a mass of 0.035 kg. If tension in the string is 60.5 N. Then speed of a wave on the string is

A string of length 50 cm and mass 12.5 g is fixed at both ends. A pipe closed at one end has a length 85 cm . When the string vibrates in its second overtone and the air column in the pipe in its first. Overtone, they produce a beats frquency of 6 Hz . It is also observed that decreasing teh tension in the string decreaes beats frequency. Neglect the end correction in the pipe and velocity of sound in air is 340 m//s . then the tension in the string is