(i)A blue coloured compound `(A)` on heating gives two product `(B)` & `( C)`.
(ii)A metal `(D)` is deposited on passing hydrogen through heated `(B)`.
(iii)The solution of `(B)` in `HCl` on treatment with the `[Fe(CN)_(6)]^(4-)` gives a chocolate brown coloured precipitate of compound `(E)`.
(iv)`(C )` turns lime water milky which disappears on continuous passage of `(C )` forming a compound `(F)`.
Identigfy `(A)` to `(F)` and give chemical equations for the reactions at step (i) to (iv).

Answer

`A = 2CuCO_(3).Cu(OH)_(2), B=CuO,C=CO_(2), D=Du, E=Cu_(2)[Fe(CN)_(6)], F = Ca(HCO_(3))_(2)`. Azurite