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PCl (5) hArr PCl (3) + PCl(3) If the e...

`PCl _(5) hArr PCl _(3) + PCl_(3)`
If the equilibrium cnstant `(K _(c))` for the above reaction at 500 K is `1.79` and the equilibrium concentration of `PCl _(5) and PCl _(3)` are `1.41` M and `1.59M,` respectively, then the concentration of `Cl _(2)` is approximately.

A

`1.26M`

B

`3.59M`

C

`0.59M`

D

`1.59M `

Text Solution

Verified by Experts

The correct Answer is:
D
Equilibrium constant `(K_(C)) = ([PCl_(3)][Cl_(2)])/([PCl_(5)])`
`1.79 = (1.59 xx [Cl _(2)])/(1.41)`
`[Cl_(2)] = (1.79 xx 1.41)/(1.59)=1.587 ~~ 1.59m`
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