In reactin (1), `XeF_(6)` hydrolysis to form HF and X. In reaction (2), `XeF_(6)` on partial hydrolysis from HF, Y and Z.
The product X,Y,Z respectively, are

Options

A. `Xe O _(3), Xe, XeO_(2) F_(2)`
B. `XeO _(3), XeOF_(4), XeO_(2)F_(2)`
C. `Xe, XeOF_(4), XeO _(2) F_(2)`
D. `XeO _(3), O _(2), XeO _(2)F_(2)`

Answer

B

Explanation

Complete hydrolysis of `XeF_(6)` produces xenon trioxide.
`XeF_(6) + 3H _(2) O to Xe O _(3) + 6HF`
Whereas partial hydrolysis of `XeF_(6) ` from different products.
`XeF_(6) + 2H_(2) O to XeO_(2)F_(2) + 4HF`
`Xe F_(6) + H_(2)O to Xe O F_(4) + 2HF`