The radius of `""_(72)Te^(125)` nucleus is 6 fermi. The radius of `""_(13)Al^(27)` nucleus in meters is

Options

A. `3.6 xx 10^(-12) m`
B. `3.6 xx 10^(-15) m`
C. `7.2 xx 10^(-8) m`
D. `7.2 xx 10^(-15) m`

Answer

B

Explanation

`R =R_(0)A^(1/3)`
` R_(1)/R_(2) = (A_(1)/A_(2))^(1//3)`
Given,`R_(1)=6 ,A_(1)=125,A_(2)=27,R_(2)= ?`
`rArr 6/R_(2)=(125/27)^(1/3)`
`R_(2)=3.6 fermi``:. R_(2)=3.6 xx 10^(-15)` m.