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Calculate the standard enthalpy of react...

Calculate the standard enthalpy of reaction at `25^(@)C` temperature for the following reaction:
`C_(6)H_(6)(l)+(15)/(2)O_(2)(g) to 6CO_(2)(g)+3H_(2)O(l)`
Given:The standard enthalpy of formation of `C_(6)H_(6),CO_(2)(g) and H_(2)O(l)`are 49.0 kJ`*mol^(-1),-393.5kJ*mol^(-1) and -285.8kJ*mol^(-1)` respectively.

Text Solution

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`C_(6)H_(6)(l)+(15)/(2)O_(2)(g) to 6CO_(2)(g)+3H_(2)O(l)`
Standard heat of reactio for this reaction is
`DeltaH^(0)=6xxDeltaH_(f)^(0)(CO_(2)(g)]+3xxDeltaH_(f)^(0)[H_(2)O(l)]-1xxDeltaH_(f)^(0)[C_(6)H_(6)(l)]-(15)/(2)DeltaH_(f)^(0)[O_(2)(g)]`
`=6xx(-393.5)+3xx(-285.8)-1xx(49.0)-(15)/(2)xx0`
`=-3267.4kJ" "[because DeltaH_(f)^(0)[O_(2)(g)]=0`
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