`DeltaU^(0)` for combustion of methane is `-XkJ*mol^(-1)`. The value of `DeltaH^(0)` is-

Options

A. `=DeltaU^(0)`
B. `gtDeltaU^(0)`
C. `ltDeltaU^(0)`
D. 0

Answer

C

Explanation

The combustion reaction for methane is-
`CH_(4)(g)+2O_(2)(g)toCO_(2)(g)+2H_(2)O(l)`
For this reaction, `Deltan=1-(1+2)=-2`
We know, `DeltaH^(0)=DeltaU^(0)+DeltanRT`
For the above combustion reaction, `DeltaH^(0)=-X-2RT`
As T is positive, `DeltaH^(0) lt DeltaU^(0)`.