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In a process, 701J of heat is absorbed b...

In a process, 701J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy for the process?

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Verified by Experts

Given: `q=+701J and w=-394J` (-ve sign as the work is done by the system)
Now, `DeltaU=q+w or, DeltaU=(701-394)J=+307J`
So, the change in internal energy of the system=+307 J.
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