Calculate the pH of the following solution:
2g of TIOH dissolved in water to give 2 litre of solution.

Explanation

Concentration of TIOH,
`[TIOH]=(2)/((204+16+1))xx(1)/(2)(M)+4.52xx10^(-3)(M)`
[gram-atomic mass of Tl=204g`*mol^(-1)`]
So, in this solution, `[OH^(-)]=4.52xx10^(-3)(M)`
`therefore pOH=-log_(10)[OH^(-)]=-log_(10)(4.52xx10^(-3))=2.34`
and pH=14-pOH=14-2.34=11.66