Number of hydrogen ions present in 10 million part of `1.33cm^3` of pure water at `25^(@)C` is-

Options

A. 6.023 million
B. 60 million
C. 80.1 million
D. 80.23 million

Explanation

At `25^(@)C` in pure water, `H^+(aq)=10^(-7)mol*L^(-1)` In 1000 cc of pure water, amount of `H^(+)(aq)=10^(-7)mol` So, in million of `1.33cm^3` of pure water, the amount of `H^+(aq)` ions `=10^(-7)molxx1/(1000)xx1.33xx10^(-7)`
`=1.33xx106(-17)mol`
Hence, the number of `H^+`(aq) ions in 10 million of `1.33cm^3` of pure water `=1.33xx10^(-17)xx6.023xx10^(23)`
`=8.01xx10^6=8.01` million